Integrand size = 15, antiderivative size = 51 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^2 x}{d^2}-\frac {(b c-a d)^2}{d^3 (c+d x)}-\frac {2 b (b c-a d) \log (c+d x)}{d^3} \]
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Time = 0.03 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {45} \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=-\frac {(b c-a d)^2}{d^3 (c+d x)}-\frac {2 b (b c-a d) \log (c+d x)}{d^3}+\frac {b^2 x}{d^2} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {b^2}{d^2}+\frac {(-b c+a d)^2}{d^2 (c+d x)^2}-\frac {2 b (b c-a d)}{d^2 (c+d x)}\right ) \, dx \\ & = \frac {b^2 x}{d^2}-\frac {(b c-a d)^2}{d^3 (c+d x)}-\frac {2 b (b c-a d) \log (c+d x)}{d^3} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^2 d x-\frac {(b c-a d)^2}{c+d x}+2 b (-b c+a d) \log (c+d x)}{d^3} \]
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Time = 0.22 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.24
method | result | size |
default | \(\frac {b^{2} x}{d^{2}}+\frac {2 b \left (a d -b c \right ) \ln \left (d x +c \right )}{d^{3}}-\frac {a^{2} d^{2}-2 a b c d +b^{2} c^{2}}{d^{3} \left (d x +c \right )}\) | \(63\) |
norman | \(\frac {\frac {b^{2} x^{2}}{d}-\frac {a^{2} d^{2}-2 a b c d +2 b^{2} c^{2}}{d^{3}}}{d x +c}+\frac {2 b \left (a d -b c \right ) \ln \left (d x +c \right )}{d^{3}}\) | \(68\) |
risch | \(\frac {b^{2} x}{d^{2}}+\frac {2 b \ln \left (d x +c \right ) a}{d^{2}}-\frac {2 b^{2} \ln \left (d x +c \right ) c}{d^{3}}-\frac {a^{2}}{d \left (d x +c \right )}+\frac {2 a b c}{d^{2} \left (d x +c \right )}-\frac {b^{2} c^{2}}{d^{3} \left (d x +c \right )}\) | \(86\) |
parallelrisch | \(\frac {2 \ln \left (d x +c \right ) x a b \,d^{2}-2 \ln \left (d x +c \right ) x \,b^{2} c d +d^{2} x^{2} b^{2}+2 \ln \left (d x +c \right ) a b c d -2 \ln \left (d x +c \right ) b^{2} c^{2}-a^{2} d^{2}+2 a b c d -2 b^{2} c^{2}}{d^{3} \left (d x +c \right )}\) | \(99\) |
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Time = 0.22 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.80 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^{2} d^{2} x^{2} + b^{2} c d x - b^{2} c^{2} + 2 \, a b c d - a^{2} d^{2} - 2 \, {\left (b^{2} c^{2} - a b c d + {\left (b^{2} c d - a b d^{2}\right )} x\right )} \log \left (d x + c\right )}{d^{4} x + c d^{3}} \]
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Time = 0.19 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.18 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^{2} x}{d^{2}} + \frac {2 b \left (a d - b c\right ) \log {\left (c + d x \right )}}{d^{3}} + \frac {- a^{2} d^{2} + 2 a b c d - b^{2} c^{2}}{c d^{3} + d^{4} x} \]
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Time = 0.22 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.31 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^{2} x}{d^{2}} - \frac {b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}}{d^{4} x + c d^{3}} - \frac {2 \, {\left (b^{2} c - a b d\right )} \log \left (d x + c\right )}{d^{3}} \]
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Time = 0.29 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.92 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {{\left (d x + c\right )} b^{2}}{d^{3}} + \frac {2 \, {\left (b^{2} c - a b d\right )} \log \left (\frac {{\left | d x + c \right |}}{{\left (d x + c\right )}^{2} {\left | d \right |}}\right )}{d^{3}} - \frac {\frac {b^{2} c^{2} d}{d x + c} - \frac {2 \, a b c d^{2}}{d x + c} + \frac {a^{2} d^{3}}{d x + c}}{d^{4}} \]
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Time = 0.26 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.39 \[ \int \frac {(a+b x)^2}{(c+d x)^2} \, dx=\frac {b^2\,x}{d^2}-\frac {a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2}{d\,\left (x\,d^3+c\,d^2\right )}-\frac {\ln \left (c+d\,x\right )\,\left (2\,b^2\,c-2\,a\,b\,d\right )}{d^3} \]
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